SOLUTION: The length of a rectangle is 4 in. greater than the width. The perimeter of the rectangle is 24 in. Find the dimensions of the rectangle.

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Question 100967This question is from textbook Algebra I
: The length of a rectangle is 4 in. greater than the width. The perimeter of the rectangle is 24 in. Find the dimensions of the rectangle. This question is from textbook Algebra I

Answer by doukungfoo(195) About Me  (Show Source):
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perimeter of a rectangle is 2 times Length plus 2 times width
P=2L+2W
Lets set the width equal to x
Width = x
Given: length of a rectangle is 4 in. greater than the width
Express this in terms of x
Length = x + 4
Given: perimeter of the rectangle is 24 in.
Now we can use the perimeter formula to solve for x
P=2L+2W
24=2%28x%2B4%29%2B2%28x%29 distribute 2 over each set of ()
24=2x%2B8%2B2x combine like terms
24=4x%2B8 subtract 8 from both sides
16=4x divide both sides by 4
4=x
Answer: width is 4 inches
Now find length
Length = x + 4
Length = 4 + 4
Length = 8
Answer: legnth is 8 inches
Check answers
P=2L+2W
24 = 2(8) + 2(4)
24 = 16 + 8
24 = 24