SOLUTION: factor completly using the perfect cube factorization formula y^3+a^3=(y+a)(y^2-ay+a^2) 8y^3+1

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Question 68894: factor completly using the perfect cube factorization formula
y^3+a^3=(y+a)(y^2-ay+a^2)
8y^3+1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y^3+a^3=(y+a)(y^2-ay+a^2)
8y^3+1
=(2y)^3 + 1^3
=(2y+1)((2y)^2-2y+1)
=(2y+1)(4y^2-2y+1)
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Cheers,
Stan H.