SOLUTION: Trains A & B are traveling the the same direction on parallel tracks. Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same sta

Algebra ->  Systems-of-equations -> SOLUTION: Trains A & B are traveling the the same direction on parallel tracks. Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same sta      Log On


   



Question 442900: Trains A & B are traveling the the same direction on parallel tracks. Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same station at 4:40 p.m., what time will Train B catch up to Train A?
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Trains A & B are traveling the the same direction on parallel tracks. Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same station at 4:40 p.m., what time will Train B catch up to Train A?
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In 12 minutes (440 - 425), train A goes 16 miles (80 mph * 1/5 hour). It's 16 miles ahead when train B passes the station at 440.
Train B gains on train A at 16 mph (96 - 80).
16 miles/16 mph = 1 hour
4:40 + 1 = 5:40 PM