Question 327109: solve.
X^2+Y^2=16
Y^2=x+4
list the solutions.
thank you for the help!! Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve.
X^2+Y^2=16
Y^2=x+4
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Substitute for Y^2 and solve for "x":
X^2 + (x+4) = 16
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x^2 + x - 12 = 0
Factor:
(x+4)(x-3) = 0
x = -4 or x = 3
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If x = -4, y^2=9, and y = +-3
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If x = 3, y^2 = 7, and y = +-sqrt(7)
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Cheers,
Stan H.
You can put this solution on YOUR website! solve.
X^2+Y^2=16
Y^2=x+4
y^2 - x - 4 = 0
----------- subtract 2 from 1
(x+4)*(x-3) = 0
x = -4
y = 0
--> (-4,0)
--------
x = +3
y = +/- sqrt(7)
--> (3,sqrt(7)) & (3,-sqrt(7))
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