SOLUTION: A cd costs 6 dollars more than an MP3 file. john bought two cd's and three MP3 files for 59.50 dollars. write a system of equations to represent the situation. how much did each CD

Algebra ->  Systems-of-equations -> SOLUTION: A cd costs 6 dollars more than an MP3 file. john bought two cd's and three MP3 files for 59.50 dollars. write a system of equations to represent the situation. how much did each CD      Log On


   

Question 29641: A cd costs 6 dollars more than an MP3 file. john bought two cd's and three MP3 files for 59.50 dollars. write a system of equations to represent the situation. how much did each CD cost?
Answer by ikdeep(226) About Me  (Show Source):
You can put this solution on YOUR website!
Let cost of cd = $c
Let cost of mp3 = $m
according to first condition i.e A cd costs 6 dollars more than an MP3 file..we get the following equstion.....
c - 6 = m .....................(1)
according to second condition i.e two cd's and three MP3 files for 59.50 dollars,....we get the following equstion.....
2c + 3m = 59.50...
By substitution method you can solve further and get the cost of cd...
Still if you won't be able to solve further, contact me again.
hope this will help you.
Please feel free to revert back for any further queries.