SOLUTION: If {{{ r(x)= sqrt(x+1)-2 }}}; find
A. r(x)<0
B. r(x)>0
I'm completely lot. I plugged in random values for x to get y. Like this:
When x=8; y=1
I'm not sure what to do
Algebra ->
Square-cubic-other-roots
-> SOLUTION: If {{{ r(x)= sqrt(x+1)-2 }}}; find
A. r(x)<0
B. r(x)>0
I'm completely lot. I plugged in random values for x to get y. Like this:
When x=8; y=1
I'm not sure what to do
Log On
Question 1073578: If ; find
A. r(x)<0
B. r(x)>0
I'm completely lot. I plugged in random values for x to get y. Like this:
When x=8; y=1
I'm not sure what to do from there...
Thank you so much!!!! Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! It's easier to graph it.
.
.
. .
.
.
.
Or at the very least, solve for,
Then you know the dividing line between positive and negative values.
Then you can divide the regions that are less than zero and those that are greater than zero.
.