SOLUTION: 1) Use the arithmetic sequence of numbers 2, 4, 6, 8, 10… to find the following: a) What is d, the difference between any two consecutive terms? Answer:

Algebra ->  Sequences-and-series -> SOLUTION: 1) Use the arithmetic sequence of numbers 2, 4, 6, 8, 10… to find the following: a) What is d, the difference between any two consecutive terms? Answer:       Log On


   



Question 87087: 1) Use the arithmetic sequence of numbers 2, 4, 6, 8, 10… to find the following:
a) What is d, the difference between any two consecutive terms?
Answer:
Show work in this space.


b) Using the formula for the nth term of an arithmetic sequence, what is 101st term? Answer:
Show work in this space.


c) Using the formula for the sum of an arithmetic sequence, what is the sum of the first 20 terms?
Answer:
Show work in this space.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a)
The difference is the factor between each term. So going from 2 to 4, 4 to 6, 6 to 8, and 8 to 10 you see that its adding 2 each time. To verify, pick one term and subtract the previous term from it. So lets say I choose 10: I'm going to subtract 8 from it (which is the previous term) to get a difference of 2. If I pick 8, and subtract 6, I get a difference of 2.

So the difference is: d=2



b)
Using what we found earlier, I know that the sequence counts up by 2 each term. So if I'm at 2 (the 1st term) and I go to 4, this means I increase by 2 each term. If I let n=0 then the term is 2, and if I let n=1 then the term is 4. This basically tells me that the arithmetic sequence is 2n+2. To verify, simply plug in the 1st term (n=0) and you'll get 2. Plug in the 2nd term (n=1) you'll get 4, if I let n=2 I get 6, etc. If I wanted to know the 101st term, let n=100 (remember zero is the first term) and it comes to
2%2Ahighlight%28100%29%2B2=202 So the 101st term is 202


c)Now lets find the sum of the first 20 terms

Using the sum of arithmetic series formula:
s=%28n%2F2%29%2A%28a%5B1%5D%2Ba%5Bn%5D%29 a[1]=first term, a[n]=nth term (ending term which is the 20th term), and n is the number of terms
Since we know the first term is 2, we know that a%5B1%5D=2.
So lets calculate the 20th term.

Let n=19(remember we started at n=0)

a%5B19%5D=2%2819%29%2B2=38%2B2=40

So the term a%5Bn%5D=40

Now lets evaluate the sum
s=%2820%2F2%29%2A%282%2B40%29 Plug in values.
s=%2810%29%2A%2842%29Simplify
s=420 So the sum of the first 20 terms is 420.