1,4,7,10,13
To get the 2nd term 4, you add 3 to the 1st term 1 time
To get the 3rd term 7, you add 3 to the 1st term 2 times
To get the 4th term 10, you add 3 to the 1st term 3 times.
To get the 5th term 13, you add 3 to the 1st term 4 times.
To get the nth term an, you add 3 to the 1st term (n-1) times.
an = a1 + (n-1)·d
Substitute a1 = first term = 1 and d = 3 (the common
difference between any term and the one before it.
an = 1 + (n-1)·3 = 1 + 3(n-1) = 1 + 3n - 3 = 3n-2.
an = 3n-2
Substitute n=20:
a20 = 3(20)-2 = 60-2 = 58.
Checking:
1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58
Edwin