Question 199771: Hello and Thank You for your help.
I know the answewr to my problem is 10 years. I kept subtracting to get the answer. I don't know how to write an equation to solve the problem. The question is
Bill will put aside $100 per month this year for retiremenmt. Next year he will put away $200 per month the third year $300 per month. Each year will increase by $100 per month. How many years will Bill save to reach $66,000?
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! You basically have the sequence:
12*100,
12*200,
12*300,
12*400,
12*500, ...
note: I'm multiplying by 12 since he deposits money 12 times a year.
and you're adding up the terms to get:
12*100+12*200=12*300,
12*100+12*200+12*300=12*600,
12*100+12*200+12*300+12*400=12*1000,
12*100+12*200+12*300+12*400+12*500=12*1500, ...
and you want to know which partial sum will be equal to 66,000.
So you basically want to know when 12*100+12*200+12*300+12*400+12*500+...=66000
We can factor out the GCF 12*100 to get: 12*100(1+2+3+4+5+....)=66000
and we're left with a very familiar series in the parenthesis.
It turns out that (this is a well known formula).
So the equation then becomes:
where "n" is the number of years.
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Start with the given equation.
Divide both sides by 12.
Reduce
Divide both sides by 100.
Reduce.
Multiply both sides by 2.
Multiply
Distribute
Subtract 110 from both sides.
Notice we have a quadratic in the form of where , , and
Let's use the quadratic formula to solve for "n":
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the possible solutions are or
Recall that the value of "n" is the number of years. Since you cannot have a negative year, this excludes
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Answer:
So the answer is which means that it will take 10 years to save up to $66,000.
If you have any questions, email me at jim_thompson5910@hotmail.com
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