SOLUTION: The length of a patio is four times its width. The perimeter is 80 feet. Find the length and the width. Explain your work with diagrams, algebra, and words.

Algebra ->  Rectangles -> SOLUTION: The length of a patio is four times its width. The perimeter is 80 feet. Find the length and the width. Explain your work with diagrams, algebra, and words.      Log On


   

Question 947326: The length of a patio is four times its width. The perimeter is 80 feet. Find the length and the width. Explain your work with diagrams, algebra, and words.
Answer by josgarithmetic(39799) About Me  (Show Source):
You can put this solution on YOUR website!
Length, L;
Width, w;
p, perimeter;
-
L=4w.
p=80.
2w%2B2L=p;
2w%2B2L=80
highlight_green%282w%2B2%284w%29=80%29

You can draw a diagram:
Draw a rectangle. Label the longer dimension L, and label the shorter dimension w, and include with it, L=4w on the longer dimension.