SOLUTION: the length of a rectangle is 8 more than the width. The perimeter of the rectangle is 64. What is the width of the rectangle?
Algebra ->
Rectangles
-> SOLUTION: the length of a rectangle is 8 more than the width. The perimeter of the rectangle is 64. What is the width of the rectangle?
Log On
Question 660943: the length of a rectangle is 8 more than the width. The perimeter of the rectangle is 64. What is the width of the rectangle? Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website! p = 2(l+w) = 64
l = 8 + w
2l + 2w = 64
2(8+w) + 2w = 64
16 + 2w + 2w = 64
4w = 64-16
4w = 48
w =12
l = 12+8=20
Proof
2(12+20)=2(32)=64
P=64
(