SOLUTION: Given the quadratic equation y=2x^2+4x-1 find the coordinates of the vertex

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Question 381629: Given the quadratic equation y=2x^2+4x-1 find the coordinates of the vertex
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex      

finding the vertex by completing the square

y=2x^2+4x-1 

y = 2(x^2 + 2) - 1

y = 2[(x+1)^2-1} -  1

y = 2(x+1)^2 -2 -  1

y = 2(x+1)^2 -3

vertex is Pt(-1,-3)