SOLUTION: The preview of a rectangle is 136 feet. The length is seven feet less than four times the width. Find the length and width.

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Question 212814: The preview of a rectangle is 136 feet. The length is seven feet less than four times the width. Find the length and width.
Found 2 solutions by checkley77, drj:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean the perimeter:
2L+2W=136
L=4W-7
2(4W-7)+2W=136
8W-14+2W=136
10W=136+14
10W=150
W=150/10
W=15 FEET IS THE WIDTH.
L=4*15-7=60-7=53 FEET IS THE LENGTH.
PROOF:
2*53+2*15=136
106+30=136
136=136

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 136 feet. The length is seven feet less than four times the width. Find the length and width.

Step 1. Let l = 4w-7 length of rectangle and let w be the width. And we are given that length is seven feet less than 4 times the width.

Step 2. Let P = 136 ft be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,

P=4w-7%2B4w-7%2Bw%2Bw

P=10w-14

P=10w-14=136

Step 3. Add 14 to both sides of equation to get 4w by itself


10w-14%2B14=136%2B14

10w=150

Step 4. Divide 10 to both sides of equation

10w%2F10=150%2F10

w=+15+

l=4w-7=60-7=53 ft

Step 5. w = 15 is the width of the rectangle and length is 53 since

Check P=10w-14=10(15)-14=136 So w = 15 ft and l = 53 ft is the solution.

Hope the above steps were helpful. Good luck in your homework and studies!

Respectfully
Dr J

Hope you understood and followed the steps. Good luck in your studies. Dr J

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