SOLUTION: One half area of a rectangular garden is 54m . If the triple of the width exceeds twice the length by 3 meter , Find the perimeter
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-> SOLUTION: One half area of a rectangular garden is 54m . If the triple of the width exceeds twice the length by 3 meter , Find the perimeter
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You can put this solution on YOUR website! One half area of a rectangular garden is 54m .triple of
Then the total area = 108 sq/m
L * w = 108
L =
If triple the width exceeds twice the length by 3 meter,
3w = 2L + 3
replace L with
3w = 2() + 3
3w = + 3
multiply equation by w
3w^2 = 216 + 3w
A quadratic equation
3w^2 - 3w - 216 = 0
simplify, divide by 3
w^2 - w - 72 = 0
Factors to
(w-9)(w+8) = 0
the positive solution
w = 9 m is the width
Find L
L = 108/9
L = 12 m is the length
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"Find the perimeter
P = 2(12) + 2(9)
p = 42 m is the perimeter
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Check our solutions in the statement
"If triple the width exceeds twice the length by 3 meters"
3(9) = 2(12) + 3
