SOLUTION: The length of a rectangletter is 10 feet more than twice the width. The area of the rectangle is 48 square feet. Find the length and the width of the rectangle

Algebra ->  Rectangles -> SOLUTION: The length of a rectangletter is 10 feet more than twice the width. The area of the rectangle is 48 square feet. Find the length and the width of the rectangle       Log On


   

Question 1053556: The length of a rectangletter is 10 feet more than twice the width. The area of the rectangle is 48 square feet. Find the length and the width of the rectangle

Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let w be the width of the rectangle. Then the length of the rectangle is 2w+10. So:
w(2w+10)=48
2w²+10w-48=0
w²+5w-24=0
(w+8)(w-3)=0
w=3 or -8.
Throwing out the negative result, we get the width to be 3 ft., and the length to be 16 ft. ☺☺☺☺.