SOLUTION: Using the formula {{{f(x)=x^2-2x+1}}}, find if it has a maximum or minimum and give that point. Also give x-intercepts.

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Question 461376: Using the formula f%28x%29=x%5E2-2x%2B1, find if it has a maximum or minimum and give that point. Also give x-intercepts.
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Using the formula f%28x%29=x%5E2-2x%2B1, find if it has a maximum or minimum and give that point. Also give x-intercepts.
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Find minimum/maximum point
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This function represents a the standard form of an equation for a parabola, f%28x%29=ax%5E2%2Bbx%2Bc.
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There is an easy way to tell if the parabola has a maximum or a minimum when the equation is in this form. If the coefficient of the x-squared term is positive the parabola opens upward, and the the function has a minimum at the vertex. If the coefficient is negative, the parabola opens downward, and the the function has a maximum value.
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In your equation, the coefficient is 1 because you have x%5E2. (Remember, if no coefficient is shown, it is understood to be 1.) Your parabola opens upward, and the function has a minimum value.
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Parabolas have one maximum or minimum value located at the vertex. To find the vertex of your parabola, we use the formula, x = -b/2a. Looking at the equation, we see that b is -2 and a is 1, so x = -b/2a = -(-2)/(2(1)) = 1. To find the y-value of the vertex, substitute 1 for x in the equation.
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y=x%5E2-2x%2B1=%281%29%5E2-2%281%29%2B1%29=0
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Find the x-intercepts
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The x-intercepts are the points where the parabola intersects the x-axis. To find the x-intercepts we set f(x) = 0. and solve for x.
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f%28x%29=x%5E2-2x%2B1
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Set the function equal to zero.
0=x%5E2-2x%2B1
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Invert the order of the equation.
x%5E2-2x%2B1=0
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This is a quadratic equation. We have two choices for solving it: factoring, or the quadratic formula. In this case the equation looks pretty east to factor.
%28x-1%29%28x-1%29=0
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Notice that both factors are the same, so
x-1=0
x=1
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This tells us that when f(x) is 0, x is 1 and the x-intercept is the point (1,0).
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A quick check using substitution, gives us
f%28x%29=x%5E2-2x%2B1
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0=%281%29%5E2-2%281%29%2B1
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0=1-2%2B1
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0=0 (true)
Take a look at the graph:
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graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2-2x%2B1%29

Hope this helps!
Ms. Figgy
math-in-the-vortex