SOLUTION: Solve equation: x^2+4x+3=0 -8q^2-2q+1=0

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Question 367638: Solve equation: x^2+4x+3=0
-8q^2-2q+1=0
Answer by amoresroy(361) About Me  (Show Source):
You can put this solution on YOUR website!
Solve equation: x^2+4x+3=0
(x+3)(x+1) = 0
If (x+3) = 0
x = -3
If (x+1) = 0
x = -1
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-8q^2-2q+1=0
(-4q + 1)(2q + 1) = 0
If (-4q + 1) = 0
q = 1/4
If (2q + 1) = 0
q = -1/2