SOLUTION: Please help me solve this equation: (x^2-2x-3/x+1)/(x^2+x-12-x^2)-1 I can not seem to get this subject at all and i Have a test tomorrow so could you please do this problems step

Algebra ->  Rational-functions -> SOLUTION: Please help me solve this equation: (x^2-2x-3/x+1)/(x^2+x-12-x^2)-1 I can not seem to get this subject at all and i Have a test tomorrow so could you please do this problems step      Log On


   



Question 29104: Please help me solve this equation:
(x^2-2x-3/x+1)/(x^2+x-12-x^2)-1
I can not seem to get this subject at all and i Have a test tomorrow so could you please do this problems step by step
Thank You
Alyssa

Found 2 solutions by sdmmadam@yahoo.com, longjonsilver:
Answer by sdmmadam@yahoo.com(530) About Me  (Show Source):
You can put this solution on YOUR website!
The correct problem should be something like this:
{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1

{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1
= {[(x-3)(x+1)/(x+1)]divided by [(x+4)(x-3)/(x^2)]}-1
={[(x-3)]divided by [(x+4)(x-3)/(x^2)]}-1 (cancelling (x+1)
={[(x-3)]mulitplied by[(x^2)/(x+4)(x-3)]}-1
(if the division sign is changed into multiplication symbol then then the fraction after the division sign is reciprocated)
={[(x-3)]X[(x^2)/(x+4)(x-3)]}-1
={[(x-3)(x^2)/(x+4)(x-3)]}-1
=[(x^2)/(x+4)]-1 (cancelling (x-3)
=[(x^2)-1(x+4)]/(x+4)
= (x^2-x-4)/(x+4)

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
First off, being picky, this is not an equation, since there is no equals sign. All you can do is just simplify the expression, so that is what i shall do :-)

I am assuming a few things, as i am not sure, from your question:
1. the final -1 is not a power
2. the final -1 is on the denominator
3. as you have written it, the equation is still dubiously written as it looks like +%28x%5E2-2x-3%2Fx%2B1%29%2F%28%28x%5E2%2Bx-12-x%5E2%29-1%29+

I am assuming it should be: +%28%28x%5E2-2x-3%29%2F%28x%2B1%29%29%2F%28%28x%5E2%2Bx-12-x%5E2%29-1%29+, in which case:
+%28%28%28x-3%29%28x%2B1%29%29%2F%28x%2B1%29%29%2F%28%28x-12%29-1%29+
+%28x-3%29%2F%28x-11%29+

jon.