SOLUTION: I have got all my problems worked out except this one. I have a problem when it comes to the elimination method. PLEASE EXPLAIN! 0.05x+0.25y=66 0.15x+0.05y=72
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-> SOLUTION: I have got all my problems worked out except this one. I have a problem when it comes to the elimination method. PLEASE EXPLAIN! 0.05x+0.25y=66 0.15x+0.05y=72
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Question 173957: I have got all my problems worked out except this one. I have a problem when it comes to the elimination method. PLEASE EXPLAIN! 0.05x+0.25y=66 0.15x+0.05y=72 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! PLEASE EXPLAIN!
0.05x+0.25y=66
0.15x+0.05y=72
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To use elimination (and then substitution) multiply one or both eqns to get the same coeffs for one of the variables.
In these 2, multiplying the 1st eqn by 3 will give the same coeffs for x
0.05x+0.25y=66
0.15x+0.75y=198 eqn1 times 3
0.15x+0.05y=72 Then subtract 2 from 1
0.0x+ 0.70y=126
7y = 1260
y = 180
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Sub for y into either eqn
0.05x + 0.25*180 = 66
5x + 4500 = 6600
5x = 2100
x = 420
