SOLUTION: How do you graph a circle with the equation 3x^2 + 3y^2 =27

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Question 144315: How do you graph a circle with the equation 3x^2 + 3y^2 =27
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2+%2B+3y%5E2+=27
Divide by 3--> x%5E2+%2B+y%5E2+=+9
That's a circle of radius 3 about the origin.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you graph a circle with the equation 3x^2 + 3y^2 =27
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Divide thru by 3 to get:
x^2 + y^2 = 9
Circle with center at (0,0) and radius = 3
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Cheers,
Stan H.