SOLUTION: Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together. (simplify your answerr. Type an

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together. (simplify your answerr. Type an       Log On


   



Question 157157: Jack usually mows his lawn in 6 hours. Marilyn can mow the same yard in 7 hours. How much time would it take for them to mow the lawn together. (simplify your answerr. Type an integer, proper fraction or mixed number)
Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!

Let x=amount of time it takes them both working together to mow the yard
Jack mows at the rate of 1/6 yard per hour
Marilyn mows at the rate of 1/7 yard per hour
Together they mow at the rate of 1/6 +1/7 or 7/42 + 6/42=13/42 yard per hour
So, our equation to solve is:
(13/42)*x=1 (1 yard, that is) multiply each side by 42
13x=42 divide each side by 13
x=42/13 or 3 3/13 hour
CK
(1/6)(42/13)=7/13
(1/7)(42/13)=6/13
7/13 + 6/13=13/13 or 1 yard
Hope this helps---ptaylor