SOLUTION: Ed can do a job in 4 days. when ed and maymay work together, it would take them 2 and 1/3 days. How long would the job take maymay to do it alone?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Ed can do a job in 4 days. when ed and maymay work together, it would take them 2 and 1/3 days. How long would the job take maymay to do it alone?      Log On


   



Question 119287: Ed can do a job in 4 days. when ed and maymay work together, it would take them 2 and 1/3 days. How long would the job take maymay to do it alone?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
Ed can do a job in 4+days
Ed and Maymay work together 2+%281%2F3%29 days
How long would the job take Maymay to do it alone?
Let the completed job be equal to +1
Let Maymay’s time be y

+%282%281%2F3%29%29%2F4+%2B+2%281%2F3%29%2Fy+=+1………. multiply both sides by 4y

%287%2F3%29%2Ay+%2B+%287%2F3%29%2A4+=+4y+……….

%287y%2F3%29+%2B+%2828%2F3%29++=+4y+……….

%287y%2F3%29+%2B+%2828%2F3%29++=+4y+………. multiply both sides by 3

7y+%2B+28+=+12y+……….

+28+=+12y+-+7y++……….

+28+=+5y++……….

+28+%2F5=+y++……….

+y+=+5%283%2F5%29++……….

check

+2%281%2F3%29%2F4+%2B+2%281%2F3%29%2F5%283%2F5%29+++=+1……….

+%287%2F3%29%2F%284%2F1%29+%2B+%287%2F3%29%2F%2828+%2F5%29=+1……….

+7%2A1%2F%283%2A4%29+%2B+%287%2A5%29%2F%283%2A28+%29=+1……….

+7%2F%283%2A4%29+%2B+%287%2A5%29%2F%283%2A4%2A7+%29=+1……….

+7%2F%283%2A4%29+%2B+%28cross%287%29%2A5%29%2F%283%2A4%2Across%287%29+%29=+1……….

+7%2F12+%2B+5%2F12+=+1……….

+.58+%2B+.42+=+1……….

+1+=+1………