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The distance an object falls is directly proportional to the square of the time it has been falling. After 6 seconds it has fallen 1296 feet. How long will it take to fall 2304 feet?
Let the distance be = d
time taken = t
The relation given in th sum is , d proportional to (t)^2
i.e, d = k.t^2 to find the value of k substitute the
values of t= 6 sec and d = 1296
d = k.t^2
1296 = k.(6)^2
k = 1296/6.6 = 1296/36 = 36
to find the value of t substitute the values of k and d in the eq'n d = k.t^2
2304 = 36.(t)^2
2304/36 = t^2
64 = t^2
t = sqrt of 64 = 8
it will take 8 seconds to fall 2304 ft.
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