SOLUTION: I need to find the steps to from (7√(2*2*3))/6 to 7/3 √3 I have been working on it for two days now. I just don't get it.

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Question 338166: I need to find the steps to from
(7√(2*2*3))/6 to 7/3 √3
I have been working on it for two days now. I just don't get it.
Found 2 solutions by solver91311, CharlesG2:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Two days is a very long time to be working on one radical simplification problem. What have you tried? What is your approach to the problem?

John

My calculator said it, I believe it, that settles it

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
I need to find the steps to from
(7√(2*2*3))/6 to 7/3 √3
I have been working on it for two days now. I just don't get it.


let's see if I can figure it out
sqrt = square root = √

(7 * sqrt(2 * 2 * 3))/6 to 7/3 * sqrt(3)
(if I mistyped or misinterpreted, I apologize)

numerator:
7 * sqrt(12) = 7 * sqrt(4 * 3) = 7 * sqrt(2 * 2 * 3) (factoring)
7 * sqrt(12) = 7 * 2 * sqrt(3)
(there were two 2's inside the square root, sqrt(4) = 2)


denominator:
6 = 2 * 3

the 2's in the numerator and denominator cancel out

left with:
7/3 * sqrt(3)