SOLUTION: - This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have fri
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Quadratic Equations and Parabolas
-> SOLUTION: - This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have fri
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Question 825691: - This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have friendly snowball fight. Mr.Walker went inside a friends apartment with a bucket of snowballs and started to launch them from the 4th floor window. He began to gather data on the snowball path so that he could have more accuracy when he threw them. One of the snowballs had a height(in feet)from the ground that followed the equation of how long does it take the snowball to reach it's greatest height ? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
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Because the "leading coefficient" (-16) is negative, we know that this is a parabola that opens downwards. Thus, the "vertex" is the highest point (max).
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x-value of the vertex is the same as the "axis of symmetry":
t = -b/(2a)
t = -48/(2*(-16))
t = -48/(-32)
t = 48/32
t = 3/2 seconds
or
t = 1.5 seconds
