Question 818372: [ write the function in vertex form, identify the vertex,AOS, and direction of opening for:
y = -3x^2 - 10 ]
Found 2 solutions by stanbon, TimothyLamb:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! write the function in vertex form, identify the vertex,AOS, and direction of opening for y=-3x squared-10
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y = -3x^2-10
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-3(x-0)^2 = y+10
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Vertex:: (0,-10)
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AOS:: what does that mean?
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Direction: Opens downward
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Cheers,
Stan H.
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Answer by TimothyLamb(4379)  (Show Source):
You can put this solution on YOUR website! y = -3x^2 - 10
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the above quadratic equation is in standard form, with a=-3, b=-10, and c=0
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to solve the quadratic equation, by using the quadratic formula, plug this:
-3 -10 0
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic vertex is a maximum at: ( -1.67, 8.33 )
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the vertex form of the equation:
y = a(x - h)^2 + k
y = a(x + 1.67)^2 + 8.33
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the axis of symmetry is: x = -1.67
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the parabola opens downward (as suggested by a < 0)
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