SOLUTION: how do i solve: x^2-7x+3=0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: how do i solve: x^2-7x+3=0      Log On


   

Question 330307: how do i solve:
x^2-7x+3=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2-7x%2B3=0 Start with the given equation.


Notice that the quadratic x%5E2-7x%2B3 is in the form of Ax%5E2%2BBx%2BC where A=1, B=-7, and C=3


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-7%29+%2B-+sqrt%28+%28-7%29%5E2-4%281%29%283%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-7, and C=3


x+=+%287+%2B-+sqrt%28+%28-7%29%5E2-4%281%29%283%29+%29%29%2F%282%281%29%29 Negate -7 to get 7.


x+=+%287+%2B-+sqrt%28+49-4%281%29%283%29+%29%29%2F%282%281%29%29 Square -7 to get 49.


x+=+%287+%2B-+sqrt%28+49-12+%29%29%2F%282%281%29%29 Multiply 4%281%29%283%29 to get 12


x+=+%287+%2B-+sqrt%28+37+%29%29%2F%282%281%29%29 Subtract 12 from 49 to get 37


x+=+%287+%2B-+sqrt%28+37+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%287%2Bsqrt%2837%29%29%2F%282%29 or x+=+%287-sqrt%2837%29%29%2F%282%29 Break up the expression.


So the solutions are x+=+%287%2Bsqrt%2837%29%29%2F%282%29 or x+=+%287-sqrt%2837%29%29%2F%282%29