SOLUTION: My problem is:Identify the completing the squares, the vertex, the y-intercept and the axis of symmetry.
1. y=x^2+6x-11
2. y=3x^2-x+4
3. y=2x^2+7x-3
4. y=2x^2-8x-12
I need
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: My problem is:Identify the completing the squares, the vertex, the y-intercept and the axis of symmetry.
1. y=x^2+6x-11
2. y=3x^2-x+4
3. y=2x^2+7x-3
4. y=2x^2-8x-12
I need
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Question 287399: My problem is:Identify the completing the squares, the vertex, the y-intercept and the axis of symmetry.
1. y=x^2+6x-11
2. y=3x^2-x+4
3. y=2x^2+7x-3
4. y=2x^2-8x-12
I need step by step answers
my email address is gdkpw@hotmail.com
Thank you Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The best way to think of it is:
The axis of symmetry is where
is midway between the roots of the equation.
Then you find the vertex by plugging in
back into the equation to get , then
is the vertex.
An easy formula is: if the equation is in the form , then the axis of symmetry is at
The y-intercept is at
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I'll do your 1st problem:
The y-intercept is at
Now find roots:
The axis of symmetry is midway between the 2 roots which are:
root1 =
root2 = is midway between these roots, so is the axis of symmetry
And the simple formula gives the same answer:
Now plug this result back into the equation:
So, the vertex is at (-3,-20)
I'll plot the equation:
