SOLUTION: Determine the equation in standard form for this quadratic function: x intercepts at (-2 +/- √5), containing the point (-4,5)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Determine the equation in standard form for this quadratic function: x intercepts at (-2 +/- √5), containing the point (-4,5)       Log On


   

Question 1137107: Determine the equation in standard form for this quadratic function: x intercepts at (-2 +/- √5), containing the point (-4,5)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
a%28x-%28-2-sqrt%285%29%29%29%28x-%28-2%2Bsqrt%285%29%29%29=0
a%28x%2B2%2Bsqrt%285%29%29%28x%2B2-sqrt%285%29%29=0
a%28%28x%2B2%29%5E2-5%29=0
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y=a%28x%2B2%29%5E2-5a, contains point (-4,5).
5=a%28-4%2B2%29%5E2-5a
5=4a-5a=-a
a=-5
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highlight%28y=-5%28x%2B2%29%5E2%2B25%29