Question 739473: Graph the equation. Identify the focus and directrix of the parabola.
x^2=2y
How do you get that equation into the X^2=4py formula Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Graph the equation. Identify the focus and directrix of the parabola.
x^2=2y
How do you get that equation into the X^2=4py formula
Basic form of equation for a parabola that opens upward: (x-h)^2=4p(y-k),(h,k)=(x,y) coordinates of the vertex
For given equation: x^2=2y
vertex: (0,0)
axis of symmetry: x=0
4p=2
p=1/2
focus: (0,1/2) (p-distance above vertex on the axis of symmetry)
directrix(0,-1/2 (p-distance below vertex on the axis of symmetry)
see graph below as a visual check:
(