SOLUTION: Write the equation in Ax^2 + Bx^2 + Cy^2 +Dx +Ey + F = 0 form. (x-2)^2/5 - (y+3)^2/12 = 1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the equation in Ax^2 + Bx^2 + Cy^2 +Dx +Ey + F = 0 form. (x-2)^2/5 - (y+3)^2/12 = 1      Log On


   

Question 608536: Write the equation in Ax^2 + Bx^2 + Cy^2 +Dx +Ey + F = 0 form.
(x-2)^2/5 - (y+3)^2/12 = 1
Found 2 solutions by stanbon, lynnlo:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation in Ax^2 + Bx^2 + Cy^2 +Dx +Ey + F = 0 form.
(x-2)^2/5 - (y+3)^2/12 = 1
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Multiply thru by 60 to get:
12(x^2-4x+4) - 5(y^2+6y+9) = 60
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12x^2 - 48x + 48 -5y^2-30y-45 = 60
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12x^2 - 5y^2 -48x -30y -57 = 0
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Cheers,
Stan H.

Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
is this 1 problem or 2