SOLUTION: graph. label vertices, foci, and centers where applicable. 3. x2 _ y2 = 1 4. y2 = -8x

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Question 448899: graph. label vertices, foci, and centers where applicable.
3. x2 _ y2 = 1
4. y2 = -8x
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

3. x2 - y2 = 1  C(0,0)  and Vertices (1,0) and (-1,0)

c = sqrt%281%2B1%29=sqrt%282%29Foci (1.414,0)&(-1.414,0)

4. y2 = -8x    Vertex(0,0)  4p = -8 p = -2 Focus (-2,0)





Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius



 Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+

where Pt(h,k) is the center and a and b  are the respective vertices distances from center.



Standard Form of an Equation of an Hyperbola is  %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center  with vertices 'a' units right and left of center.

Standard Form of an Equation of an Hyperbola opening up and down is:

  %28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center  with vertices 'b' units up and down from center.



Using the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk

 where(h,k) is the vertex

 The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where  the focus is (h,k + p)