SOLUTION: A cross section of a reflector of a television satellite dish is a parabola that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A cross section of a reflector of a television satellite dish is a parabola that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be      Log On


   



Question 1206395: A cross section of a reflector of a television satellite dish is a parabola that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be placed?
A. 0.3125 ft
B. 0.78125 ft
C. 0.2500 ft
D. 1.25 ft
E. 0.625 ft
F. 1.8125 ft

Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.
.
A cross section of a reflector of a television satellite dish is a parabola
that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be placed?
A. 0.3125 ft
B. 0.78125 ft
C. 0.2500 ft
D. 1.25 ft
E. 0.625 ft
F. 1.8125 ft
~~~~~~~~~~~~~~~~~~~~~

Place the origin of the coordinate system at vertex of the parabola.
Use the vertex form equation of this parabola 

    y = ax%5E2.        (1)


At x = 2.5 ft, we are given y = 2 ft.  So, this vertex equation takes the form

    2 = a%2A2.5%5E2,  which gives  a = 2%2F2.5%5E2 = 2%2F6.25 = 8%2F25.


So, equation (1) is  

    y = %288%2F25%29%2Ax%5E2.    (2)


For the parabola with equation y = ax%5E2,  the distance from the vertex to the focus is

    f = 1%2F4a.


In our case, the distance from the vertex to the focus is   1%2F%284%2A%288%2F25%29%29 = 25%2F32 cm = 0.78125 ft.


ANSWER.  The distance from the vertex to the focus, where the filament should be placed, is 0.78125 ft.  

         Option (B).

Solved.