SOLUTION: A natural draft cooling tower is shaped like a hyperbola For more efficient cooling of power plants. The hyperbola of the tower can be molded by x^2/16 - y^2/225 = 1 with 200m heig

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Question 1205329: A natural draft cooling tower is shaped like a hyperbola For more efficient cooling of power plants. The hyperbola of the tower can be molded by x^2/16 - y^2/225 = 1 with 200m height. Find the width of the top and the narrowest in the middle
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given hyperbola:
x%5E2%2F16+-+y%5E2%2F225+=+1
with 200m+height
With "x%5E2" and "y%5E2" , we have the hyperbola centered at the origin.
This makes 200m as 100m above the x-axis and 100m below, means +y=100m.
plug it in equation
x%5E2%2F16+-+100%5E2%2F225+=+1......solve for x
x+=+%284sqrt%28409%29%29%2F3 =>exact the width of the top
x+=26.97 => approximately




Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
A natural draft cooling tower is shaped like a hyperbola For more efficient cooling of power plants.
The hyperbola of the tower can be molded by x^2/16 - y^2/225 = 1 with 200m height. Find the width of the top and the narrowest in the middle
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For the future readers of this post.

Obviously, the post formulation is made by an amateur - not a professional.

A professional will never write such problem in this way, which may perplex a reader.

A normal mathematical formulation should be like THIS:

    A natural draft cooling tower is 200 m height and is shaped like a hyperbola for more efficient cooling of power plants. 
    If the transverse axis of the hyperbola is placed horizontally at the height of the middle of the tower, 
    where its width is narrowest, then the equation of the hyperbola is  x^2/16 - y^2/225 = 1. 
    Find the width of the tower at the top and the narrowest in the middle. 


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