SOLUTION: Write the equation for the conic section in standard form and general form. https://i.ibb.co/hdXRGKm/1.jpg

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Question 1204749: Write the equation for the conic section in standard form and general form.
https://i.ibb.co/hdXRGKm/1.jpg

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!


%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1

The horizontal blue line I added:
The transverse axis extends from vertex (-7,-3/2) to vertex (-1,-3/2)
so the transverse axis is 6 units long. The semi-transverse axis is
'a' which is half of 6 or a=3.

The vertical blue line that I added:
The conjugate axis extends from midpoint of top side to midpoint of 
bottom side of defining rectangle, from (4,-1) to vertex (-4,-2)
so the conjugate axis is 1 units long. The semi-conjugate axis is
'b' which is half of 1 or b=1/2.

The center is (h,k)=(-4,-3/2) so the equation becomes in standard form

%28x%2B4%29%5E2%2F3%5E2-%28y%2B3%2F2%29%5E2%2F%281%2F2%29%5E2=1

Now if you do some work on that, you'll 

end up with this general form: 

x%5E2+-+36+y%5E2+%2B+8x+-+108y+-+74+=+0

Edwin