SOLUTION: The vertex of the parabola (x-y+1)^2=4*(x+y-5) is?

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Question 1089210: The vertex of the parabola (x-y+1)^2=4*(x+y-5) is?
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x-y%2B1=0
x%2By-5=0
Adding,
2x-4=0
2x=4
x=2
So then,
2-y%2B1=0
3-y=0
y=3
(2,3)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The vertex of the parabola (x-y+1)^2=4*(x+y-5) is?
If you square (x - y + 1), you'll get matrix%281%2C3%2C+x%5E2%2C+and%2C+y%5E2%29. 

A parabola does not contain x and y to the 2nd power.