SOLUTION: I need to solve this problem on this link Thank you https://drive.google.com/open?id=0B2SbxAb-ajtfa0dWVXF2Z0V3Vkk

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need to solve this problem on this link Thank you https://drive.google.com/open?id=0B2SbxAb-ajtfa0dWVXF2Z0V3Vkk      Log On


   



Question 1085149: I need to solve this problem on this link
Thank you
https://drive.google.com/open?id=0B2SbxAb-ajtfa0dWVXF2Z0V3Vkk

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Is there some reason you couldn't type that, instead of a linK?
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Point A is (0,5/2).
Find the points on the parabola y = x^2+1 closest to point A.
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Shift it down 1.
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Point A is (0,3/2).
Find the points on the parabola y = x^2 to point A.
Use P for a point on the parabola (x,x^2)
Distance d^2 from A to P = x^2 + (x^2 - 1.5)^2 = x^4 - 2x^2 + 2.25
f(x) = x^4 - 2x^2 + 2.25
f'(x) = 4x^3 - 4x = 0
x = 0 -- extraneous, ignore
x = -1, +1
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--> (-1,2) and (1,2)

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
Had you print your condition properly in your post, I would show you how to solve it properly.