SOLUTION: How to find the radius and the center of the equation x^2+y^2-5x+4y=16. And lastly how to graph it.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How to find the radius and the center of the equation x^2+y^2-5x+4y=16. And lastly how to graph it.       Log On


   

Question 1085148: How to find the radius and the center of the equation x^2+y^2-5x+4y=16. And lastly how to graph it.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-5x%2By%5E2%2B4y=16
x%5E2-5x%2B%285%2F2%29%5E2%2By%5E2%2B4y%2B4=%285%2F2%29%5E2%2B4%2B16
%28x-5%2F2%29%5E2%2B%28y%2B2%29%5E2=25%2F4%2B20
%28x-5%2F2%29%5E2%2B%28y%2B2%29%5E2=105%2F4

Center is ( 5/2, -2 ) and radius is %281%2F2%29sqrt%28105%29.
(Radius approx. 5.123 )