SOLUTION: I need the answer for question ( ii ) in the figure on this link please : https://drive.google.com/open?id=0B2SbxAb-ajtfRW00d2NCZWdFSW8

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need the answer for question ( ii ) in the figure on this link please : https://drive.google.com/open?id=0B2SbxAb-ajtfRW00d2NCZWdFSW8      Log On


   

Question 1084064: I need the answer for question ( ii ) in the figure on this link please :
https://drive.google.com/open?id=0B2SbxAb-ajtfRW00d2NCZWdFSW8
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Integrate the function from the left zero to the right zero or from x=0 to the right zero and double it (using symmetry).
To find the zeros,
x%5E2-8=0
%28x-sqrt%288%29%29%28x%2Bsqrt%288%29%29=0
x=2sqrt%282%29
x=-2sqrt%282%29
So,
A=int%28f%28x%29%2Cdx%2Cx=-2sqrt%282%29%2Cx=2sqrt%282%29%29
A=int%28%288-x%5E2%29%2Cdx%2Cx=-2sqrt%282%29%2Cx=2sqrt%282%29%29
A=8x-x%5E3%2F3%2BC
A=8sqrt%288%29-%28sqrt%288%29%5E3%29%2F3%2B8sqrt%288%29-%28sqrt%288%29%5E3%29%2F3
A=%2864%2F3%29sqrt%282%29