Question 1082611: What is the equation of the following graph?
circle through the points (7, 5), (3, 9), (negative 1, 5) and (3, 1)
Picture http://prntscr.com/fbpaop
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The center is at (3, 5) with radius 4. That is sufficient information.
(x-3)^2+(y-5)^2)=16. Change the sign for the center, and square the radius.
Answer by ikleyn(52832)  (Show Source):
You can put this solution on YOUR website! .
The center of the circle is the intersection of the perpendicular bisectors to the segments connecting these points:
a) (7,5) and (-1,5); and
b) (3.9) and (3,1).
The perpendicular bisector to the segment a) is vertical line x = 3.
The perpendicular bisector to the segment b) is horizontal line y = 5.
Hence, the center of the circle is the point (x,y) = (3,5).
From this point please complete the assignment on your own.
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