SOLUTION: A rhombus has sides of lenght 10cm. One of its diagonals is twice as long as the other. Calculate the length of the shorter diagonal to the nearestt mm.

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Question 964430: A rhombus has sides of lenght 10cm. One of its diagonals is twice as long as the other. Calculate the length of the shorter diagonal to the nearestt mm.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
length of short diagonal = x

side = sqrt((x/2)^2 + x^2) = 10
5x^2/4 = 100
x^2 = 80

x = sqrt(80) which is about 9 mm