SOLUTION: A rectangular piece of canvas measuring 6m by 2m is folded in half to form two sides of a tent. The length of each vertical support pole is 1.2m. What is the width of the front o

Algebra ->  Pythagorean-theorem -> SOLUTION: A rectangular piece of canvas measuring 6m by 2m is folded in half to form two sides of a tent. The length of each vertical support pole is 1.2m. What is the width of the front o      Log On


   



Question 584050: A rectangular piece of canvas measuring 6m by 2m is folded in half to form two sides of a tent. The length of each vertical support pole is 1.2m. What is the width of the front of the tent, to the nearest tenth of a metre?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
My 1st question would be: which way is the canvas
folded? It could be the long way or the short way.
If the vertical support is 1.2 m, that tells me that
the 2m side cannot be folded to make a 6 m long
tent. The sloping sides would be 1 m long, and the
vertical support would be less than 1 m.
------------
So the canvas is folded the short way making a 2 m
long tent with sloping sides = 3 m.
Use the pythagorean theorem.
+3%5E2+=+1.2%5E2+%2B+b%5E2+ where b is 1/2 the width of
the front of the tent
+b%5E2+=+3%5E2+-+1.2%5E2+
+b%5E2+=+9+-+1.44+
+b%5E2+=+7.56+
+b+=+2.75+ m
+2%2A2.75+=+5.5+ m
The width of the front of the tent is 5.5 m