SOLUTION: 4 pencils and 2 pens cost $1.08 6 pencils and 5 pens cost $2.22 find the cost of each pen and pencil

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Question 25975: 4 pencils and 2 pens cost $1.08 6 pencils and 5 pens cost $2.22 find the cost of each pen and pencil


Found 2 solutions by tran3209, kevwill:
Answer by tran3209(100) About Me  (Show Source):
You can put this solution on YOUR website!
First you can find the cost of each pen using the given information: 5 pens cost $2.22.
+2.22%2F5+ = 0.44+
So now we know each pen cost $0.44.
Now since they purchased 4 pencils and 2 pens and recieved a total of $1.08, we will find the cost of each pencil.
Suppose the cost of pencils is "x".
+4x+%2B+2%280.44%29+=+1.08+ The 2(0.44) is the cost of 2 pens @ $0.44 each.
+4x+%2B+0.88+=+1.08+
+4x+=+0.2+ <---- Subtract 0.88 from each side.
+x+=+0.05+
The Answer: (1) Pen cost $0.88
(1) Pencil cost $0.05

Answer by kevwill(135) About Me  (Show Source):
You can put this solution on YOUR website!
I think the original solver got this one wrong.

Let x = the cost of one pencil and y = the cost of one pen. Then we have:
4x+%2B+2y+=+1.08 and
6x+%2B+5y+=+2.22
Let's multiply both sides of the first equation by 3 to get
12x+%2B+6y+=+3.24
And let's multiply both sides of the second equation by 2 to get
12x+%2B+10y+=+4.44
Now let's subtract the first equation from the second:
12x+%2B+10y+-+12x+-+6y+=+4.44+-+3.24
4y+=+1.20
y+=+0.30
Now, let's substitute 0.30 for y in the first equation:
4x+%2B+2%280.30%29+=+1.08
4x+%2B+0.60+=+1.08
Subtract 0.60 from both sides:
4x+%2B+0.60+-0.60+=+1.08+-+0.60
4x+=+0.48
x+=+0.12
So pencils cost 12 cents each, and pens cost 30 cents each.