SOLUTION: Eight times the sum of three consecutive odd integers is 210 more than ten times the middle integer. Find the integers. 8(x)+(x+2)+(x+4)=210+10(x+2)

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Eight times the sum of three consecutive odd integers is 210 more than ten times the middle integer. Find the integers. 8(x)+(x+2)+(x+4)=210+10(x+2)      Log On


   

Question 896144: Eight times the sum of three consecutive odd integers is 210 more than ten times the middle integer. Find the integers.
8(x)+(x+2)+(x+4)=210+10(x+2)
Answer by richwmiller(17219) About Me  (Show Source):
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8[(x)+(x+2)+(x+4)]=210+10(x+2)
x=13
x+2=15
x+3=17