SOLUTION: Find the first of three consecutive integers. The product of the first and the second is 34 less than the square of the third.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find the first of three consecutive integers. The product of the first and the second is 34 less than the square of the third.      Log On


   

Question 891860: Find the first of three consecutive integers. The product of the first and the second is 34 less than the square of the third.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the first of three consecutive integers. The product of the first and the second is 34 less than the square of the third.
------------
Call them n-2, n-1 and n
---
(n-2)*(n-1) = n^2 - 34
n^2 - 3n + 2 = n^2 - 34
-3n = -36
n = 12
------
--> 10, 11 & 12