SOLUTION: Find two consecutive integer whose product is 72 Let X = 1st integer Let 2x= 2nd integer 2x+x=72

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Question 52070: Find two consecutive integer whose product is 72
Let X = 1st integer
Let 2x= 2nd integer
2x+x=72
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
Product = multiplication
(x)(2x)=72
2x^2=72 [Solve for x]
2x^2/2=72/2
x^2=36 [Take the square root of both sides]
x=6
.
Checking:
(x)(2x) [Plug-in (x=6)]
(6)(2)(6)
72 [Checks out]