SOLUTION: find three consecutive odd integers whose sum is 33

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Question 140794: find three consecutive odd integers whose sum is 33
Answer by ptaylor(2198) About Me  (Show Source):
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Let n=first
Then n+2=second
and n+4=third
n+n+2+n+4=33 simplify
3n+6=33 subtract 6 from each side
3n+6-6=33-6
3n=27 divide each side by 3
n=9------------------------------------first integer
n+2=9+2=11----------------------------second integer
n+4=9+4=13-------------------------------third integer
CK
9+11+13=33
33=33

Hope this helps----ptaylor