Question 993833: given that person is in 36 and over age group, what is the probability that person applied to more than one school?
the data shows 51 for 36 and over and all together 808 total from person from diff age groups that applied to more than one school.
I thought for probability you are suppose to just take the 51 from all age group who applied to more than one which is 808. =.0631? But that is not it. Has to be 4 decimals as answer.
How do i solve this? Thanks
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! what i believe you need is:
x = the number of people who are in the 36 and over age group that applied to more than 1 school.
judging from what you wrote, i believe that number will be 51.
y = the total number of people who are in the 36 and over age group, NOT the total number of people regardless of what age group they are in.
your probability should be x/y.
for example:
51 people in the 36 and over age group applied to more than one school.
372 people are in the 36 and over age group regardless of how many schools they applied to.
the probability that a person who is in the 36 and over age group applied to more than one school would be 51 / 372.
try it and see if you get the right answer.
let me know how you do.
if you don't get the right answer after doing that, then send me the complete question, as written, and i'll take a look at it for you.
also let me know what the answer is supposed to be.
|
|
|