SOLUTION: There are 5 people and 7 chairs. How many possible combinations are there, if each person took only one chair each? I'm really stumped on this one. Please explain your solution. T

Algebra ->  Probability-and-statistics -> SOLUTION: There are 5 people and 7 chairs. How many possible combinations are there, if each person took only one chair each? I'm really stumped on this one. Please explain your solution. T      Log On


   



Question 99331: There are 5 people and 7 chairs. How many possible combinations are there, if each person took only one chair each? I'm really stumped on this one. Please explain your solution. Thanks!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There are 5 people and 7 chairs. How many possible combinations are there, if each person took only one chair each? I'm really stumped on this one. Please explain your solution. Thanks!
----------------
You want to know how many ways you can pick 5 out of seven objects.
That would be 7C5 = [7*6]/[1*2] = 21
==================
Cheers,
Stan H.