Question 981603: Let Z be a standard normal random variable. Calculate the following probabilities:
P ( Z <= -1.56)
P ( Z > -1.07)
P ( 0.88 < Z < 1.37)
I did the last one on a calculator and came up with 0.587. I'm not confident that I did it correctly. All the previous ones in the homework look like this:
P ( Z <= c) = 0.8340. How do I find the probability without the c?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Let Z be a standard normal random variable. Calculate the following probabilities:
P ( Z <= -1.56) = normalcdf(-100,-1.56) = 0.0594
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P ( Z > -1.07) = normalcdf(-1.07,100) = 0.1423
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P ( 0.88 < Z < 1.37) = normalcdf(0.88,1.37) = 0.1041
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I did the last one on a calculator and came up with 0.587. I'm not confident that I did it correctly. All the previous ones in the homework look like this:
P ( Z <= c) = 0.8340. How do I find the probability without the c?
Find the z-value with a left tail of 0.8340
Ans: invNorm(0.8340) = 0.9701
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Cheers,
Stan H.
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